$6x^2-2=5-x$
$6x^2-2-5+x=0$
$6x^2+x-7=0$
$D=b^2-4ac=1^2-4\ast 6\ast (-7)=1+168=169>0$
$x_1=\frac{-b+\sqrt{D}}{2a}=\frac{-1+\sqrt{169}}{2\ast 6}=\frac{-1+13}{12}=\frac{12}{12}=1$
$x_2=\frac{-b-\sqrt{D}}{2a}=\frac{-1-\sqrt{169}}{2\ast 6}=\frac{-1-13}{12}=\frac{-14}{12}=-\frac{7}{6}=-1\frac{1}{6}$
Ответ: при $x=-1\frac{1}{6}$ и x = 1

$y-6=y^2-9y+3$
$y-6-y^2+9y-3=0$
$-y^2+10y-9=0$
$D=b^2-4ac={10}^2-4\ast (-1)\ast (-9)=100-36=64>0$
$y_1=\frac{-b+\sqrt{D}}{2a}=\frac{-10+\sqrt{64}}{2\ast (-1)}=\frac{-10+8}{-2}=\frac{-2}{-2}=1$
$y_2=\frac{-b-\sqrt{D}}{2a}=\frac{-10-\sqrt{64}}{2\ast (-1)}=\frac{-10-8}{-2}=\frac{-18}{-2}=9$
Ответ: при y = 1 и y = 9

$4m^2+4m+2=2m^2+10m+8$
$4m^2+4m+2-2m^2-10m-8=0$
$2m^2-6m-6=0$ |: 2
$m^2-3m-3=0$
$D=b^2-4ac=(-3{)}^2-4\ast 1\ast (-3)=9+12=21>0$
$m_1=\frac{-b+\sqrt{D}}{2a}=\frac{3+\sqrt{21}}{2\ast 1}=\frac{3+\sqrt{21}}{2}$
$m_2=\frac{-b-\sqrt{D}}{2a}=\frac{3-\sqrt{21}}{2}=\frac{3-\sqrt{21}}{2}$
Ответ: при $m=\frac{3-\sqrt{21}}{2}$ и $m=\frac{3+\sqrt{21}}{2}$